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int get(Node list, int i) // returns the value of element number i;

For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then get(list, 2) will return 44. 3.11 Write and test this method:

void put(Node list, int i, int x) // inserts x as element number i;

For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then put(list, 3, 50) will change list to {22, 33, 44, 50, 55, 66, 44, 88, 99}. Hint: if i = 0, replace the value of the first node with x, and insert a new node immediately after it that contains the previous fist value. 3.12 Write and test this method:

Figure 16-1

void swap(Node list, int i, int j) // swaps the ith element with the jth element;

For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then swap(list, 2, 5) will change list to {22, 33, 77, 55, 66, 44, 88, 99}. 3.13 Write and test this method:

7:

Node merged(Node list1, Node list2) // precondition: list1 and list2 are both in ascending order; // returns: a new list that contains all the elements of list1 and // list2 in ascending order;

For example, if list1 is {22, 33, 55, 88} and list2 is {44, 66, 77, 99}, then merged(list1, list2) will return the new list {22, 33, 44, 55, 66, 77, 88, 99}. Note that the three lists should be completely independent of each other. Changing one list should have no effect upon the others. 3.14 Write and test this method:

A rm s demand for a productive resource will increase (i.e., shift up) if: (1) the product demand increases; (2) the productivity of the resource rises; (3) the prices of substitute resources rise; or (4) the prices of complementary resources fall.

void rotateLeft(Node list) // moves the first element of the specified list to its end;

For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then rotateLeft(list) will change list to {33, 44, 55, 66, 77, 88, 99, 22}. Note that no new nodes are created by this method.

3.1 3.2 3.3 3.4 3.5 Arrays are inefficient for implementing dynamic sorted lists because the insert and delete operations require moving half the elements, on average. An index array is an array whose elements are index values into another array. Linked lists provide no direct access. To find the 100th element, you have to move sequentially through the first 99 elements. Insertion at the front of a linked list has to be done differently because the link to the new node is the

start link; it is not p.next for any node p (unless you use a dummy head node).

We had to define the linked lists backwards in the BigInt class because the digits of an integer are processed from right to left in the common arithmetic operations.

A rm s demand for a resource (say, labor) depends in large part upon circumstances beyond the rm s control.

CHAP. 3]

void delete(int[] a, int n, int x) { int i = 0; // find the first index i for which a[i] > x: while (i < n && a[i] <= x) { ++i; } if (i < n-1) { System.arraycopy(a, i, a, i-1, n-i); } a[n-1] = 0; } int size(Node list) { int count = 0; while (list != null) { ++count; list = list.next; } return count; } int sum(Node list) { int sum = 0; while (list != null) { sum += list.data; list = list.next; } return sum; } void removeLast(Node list) { if (list == null || list.next == null) { throw new IllegalStateException(); } while (list.next.next != null) { list = list.next; } list.next = null; } Node copy(Node list) { if (list == null) { return null; } Node clone = new Node(list.data); for (Node p=list, q=clone; p.next != null; p=p.next, q=q.next) { q.next = new Node(p.next.data); } return clone; } Node sublist(Node list, int p, int q) { if (m < 0 || n < m) { throw new IllegalArgumentException(); } else if (n == m) { return null; } for (int i=0; i<m; i++) { list = list.next; }